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Tema 1.2 Aplicaţii fidelitatea testelor
Aplicatii – fidelitatea testelor - Baza de date SPSS (Scala de evaluare a efectelor psihologice, somatice şi pedagogice – aplicaţie fidelitatea testelor 2.sav) 1. Pentru baza de date folosita la seminarul anterior, calculati toate tipurile de fidelitate pentru intreaga scala, pe care le cunoasteti; -Pentru Alfa Cronbach Case Processing Summary N Cases
Valid Excluded
a
Total
% 111
100.0
0
.0
111
100.0
a. Listwise deletion based on all variables in the procedure. Reliability Statistics Cronbach's Alpha
N of Items .581
15
-Pentru half-split
Reliability Statistics Cronbach's Alpha
Part 1
Value N of Items
Part 2
Value N of Items
Total N of Items Correlation Between Forms Spearman-Brown Coefficient
.763 8a .280 7b 15 .298
Equal Length
.459
Unequal Length
.460
Guttman Split-Half Coefficient
.451
a. The items are: ed01, ed02, ed03, ed04, ed05, ed06, ed07, ed08. b. The items are: ed08, ed09, ed10, ed11, ed12, ed13, ed14, ed15.
-Pentru formele paralele Test for Model Goodness of Fit Chi-Square
Value
Log of Determinant of
2220.342
df
118
Sig
.000
Unconstrained Matrix Constrained Matrix
-12.214 8.979
Under the parallel model assumption
Reliability Statistics Common Variance
1.876
True Variance
.159
Error Variance
1.717
Common Inter-Item
.085
Correlation Reliability of Scale
.581
Reliability of Scale
.588
(Unbiased)
2. Identificati itemii problematici si decideti cum anume pot fi tratati ei pentru a creste consistenta interna a chestionarului. Item Statistics Mean
Std. Deviation
N
ed01
3.16
.823
111
ed02
3.71
.769
111
ed03
2.83
.866
111
ed04
3.45
.716
111
ed05
2.81
.789
111
ed06
3.43
1.434
111
ed07
2.92
.745
111
ed08
4.38
.681
111
ed09
4.41
4.428
111
ed10
3.75
.611
111
ed11
3.30
.530
111
ed12
4.15
.632
111
ed13
3.09
.615
111
ed14
3.81
.528
111
ed15
3.67
.766
111
Item-Total Statistics Corrected Item-
Cronbach's
Scale Mean if
Scale Variance
Total
Alpha if Item
Item Deleted
if Item Deleted
Correlation
Deleted
ed01
49.71
53.185
.630
.521
ed02
49.16
54.789
.532
.536
ed03
50.04
54.246
.504
.533
ed04
49.42
55.346
.523
.539
ed05
50.07
54.491
.542
.533
ed06
49.44
62.836
-.152
.630
ed07
49.95
55.563
.478
.542
ed08
48.49
55.848
.503
.543
ed09
48.46
29.834
.248
.769
ed10
49.13
57.776
.353
.559
ed11
49.57
60.380
.094
.580
ed12
48.73
57.186
.402
.555
ed13
49.78
59.944
.116
.578
ed14
49.06
60.245
.111
.579
ed15
49.20
55.068
.508
.538
-Abaterea standard ne arata ca itemi 6 si 9 sunt problematici, deoarele aceasta este mult mai mare in comparatie cu ceilalti. La itemul 9 un scor a fost introdus gresit, iar la 6 scorarea trebuie facuta invers. 3. Comparati rezultatele obtinute prin diferite metode. Case Processing Summary N
%
Cases
Valid Excluded
a
Total
32
28.8
79
71.2
111
100.0
a. Listwise deletion based on all variables in the procedure.
Reliability Statistics Cronbach's Alpha
N of Items .863
15
4. Calculati Alfa Cronbach pentru urmatoarele subscale: - simptome pedagogice : itemii 1, 2, 3, 4, 5, 7. Case Processing Summary N Cases
Valid Excludeda Total
% 111
100.0
0
.0
111
100.0
a. Listwise deletion based on all variables in the procedure.
Reliability Statistics Cronbach's Alpha
N of Items .883
6
- simptome psihologice: itemii 6, 8, 9, 10, 12, 15. Case Processing Summary N Cases
Valid
% 32
28.8
Excludeda Total
79
71.2
111
100.0
a. Listwise deletion based on all variables in the procedure.
Reliability Statistics Cronbach's Alpha
N of Items .908
6
- simptome somatice : itemii 11, 13, 14. Case Processing Summary N Cases
Valid Excluded
a
Total
% 111
100.0
0
.0
111
100.0
a. Listwise deletion based on all variables in the procedure.
Reliability Statistics Cronbach's Alpha
N of Items .579
3
5. Estimati valoarea consistentei interne daca testul ar avea 30 itemi. 30:15=2 (2x0.86):[1+(2-1)x0.86]=1.72:1.86=0.92 6. Calculati de cati itemi mai este nevoie pentru a creste fidelitatea testului la .90. [0.90(1-0.86)]:[0.86(1-0.90)]=0.126:0.226=0.55
15x0.55=8.25 15+8.25=23.25 =>testul va avea 24 de itemi =>mai e nevoie de 9 itemi 7. Calculati de cati itemi mai este nevoie pentru Scala Simptome somatice a creste fidelitatea testului la .70. [0.70x(1-0.57)]:[0.57x(1-0.70)]=0.30:0.17=1.7 3x1.7=5.1 6+3=9 =>scala va avea nevoie de 9 itemi =>mai e nevoie de 6 itemi 8. Estimati valoarea consistentei interne a Scalei Simptome pedagogice daca aceasta subscala ar avea 10 itemi. 10:6=1.66 (1.66x0.88):[1+(1.66-1)x0.88]=1.46:1.58=0.92 9. Cat ar deveni coeficientul de consistenta Interna Alfa Cronbach daca am reduce Scala Simptome pedagogice la 3 itemi? 3:6=0.5 (0.5x0.88):[1+(0.5-1)x0.86] 0.44:0.57=0.77