Exp 4.1specific Heat Capacity [PDF]

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PEKA Physics Form 4

CHAPTER 4: Heat

TITLE

:Experiment 4.1

: SPECIFIC HEAT CAPACITY OF LIQUID AND SOLID

INSTRUMENT

:NON SCIENTIFIC INVESTIGATION EXPERIMENT REPORT

INSTRUCTION: 1. Carry out the experiment in the lab to collect and record the data then interpret the data and make a conclusion. 2. Write a task report AIM

: 1. 2.

To determine the specific heat of water To determine the specific heat of aluminium

woolen cloth

Woolen cloth

8. Record the power of heater, P and determine the energy supplied by heater, Q [ Q(J) = P(W) x t(s) ] 9. Calculate the specific heat capacity of water.

Woolen cloth

8. Record the power of heater, P and determine the energy supplied by heater,Q [ Q(J) = P(W) x t(s) ] 9. Calculate the specific heat capacity of aluminium.

DISCUSSION: Page 1

PEKA Physics Form 4

CHAPTER 4: Heat

1. In both experiments, explain why woolen cloth was used to wrap the apparatus. 2. In the case of aluminium block, explain why the gaps between immersion heater and thermometer are filled with oil. 3. In both case, why did the temperature continue to rise after the power supply has been switched off?. 4. Explain why the values of specific heat capacity of water and aluminium from the experiment are higher than the actual values. Task Report Format: 1. 2. 3. 4. 5. 6. 7. 8. 9.

Date Title Aim of the experiment. Apparatus and Materials Arrangement of the apparatus . (Diagram and label). The procedure of the experiment. Result Conclusion Precaution

SKEMA

: Experiment 4.1: SPECIFIC HEAT CAPACITY OF LIQUID AND SOLID

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PEKA Physics Form 4

I CI PI 1 (PART 2)

Aim

CHAPTER 4: Heat

: 1.

To determine the specific heat of water

Apparatus and Materials: woolen cloth

CI PI 2 (PART 2)

Arrangement of apparatus :

woolen cloth CI PI 3 (PART 2)

CI PI 4 (PART 2) CIII PI 1 CIII PI 2 CIII PI 3

CIV PI 1 CIV PI 2

The procedure of the experiment.

Tabulation of data: Mass of the empty beaker, m1 / kg Mass of the beaker filled with water, m2 / kg Mass of water in the beaker, m = (m1 - m2 )/ kg

Initial temperature of water, Ѳ0 / °C Final temperature of water, Ѳ1 / °C Increase in temperature, ΔѲ =( Ѳ1 - Ѳ0) / °C

Power of heater, P = 36 W Energy supplied by the heater, Q = Pt = 36 x 5 x 60 = 10800 J Specific heat capacity of water, c = Q /m ΔѲ kg-1 °C-1

=

= ...........................J

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PEKA Physics Form 4

II CI PI 2 (PART 2)

Aim

CHAPTER 4: Heat

: 2.

To determine the specific heat of aluminium

Arrangement of apparatus :

woolen cloth

CI PI 3 (PART 2)

The procedure of the experiment.

Tabulation of data: CI PI 4 (PART 2) CIII PI 1 CIII PI 2 CIII PI 3

Mass of aluminium block, m / kg Initial temperature of water, Ѳ0 / °C Final temperature of water, Ѳ1 / °C Increase in temperature, ΔѲ =( Ѳ1 - Ѳ0) / °C

CIV PI 1 CIV PI 2

Power of heater, P = 36 W Energy supplied by the heater, Q = Pt = 36 x 5 x 60 = 10800 J Specific heat capacity of aluminium, c = Q /m ΔѲ kg-1 °C-1

CIV P 3

CIV P 4

=

= ...........................J

Discussion : 1. To reduce the loss of heat to the surroundings. 2. Oil is a better heat conductor than air, thus the heat transfer between the heater and the aluminium block and between aluminium block and the thermometer is more efficient. 3. Thermal equuilibrium has not been reached yet, hence, there is still a net flow of heat from the heater in both cases. 4. Because of the heat loss to the surroundings during the experiment. Precaution: To reduce heat loss, the experiments were carried out in still air, away from the fan or the fan is not moving.

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