31 0 363KB
1
2 3 4 5
6
7
8
9
Temperature Wind Factor of Safety Working tension (T1)
Working Stress(f1)
Loading factor; q2 = √ P2 + w2 = 1 (for no wind; P = 0) The working stress is determined by the following formula: k = f1 – ℓ2 δ2 q12Ef/24f12
k = f1 – ℓ2 δ2 q12Ef/24f12 = 883.62
= 883.62
= 883.62
= 37.062
CONDITION: 2
Temperature = 75 Wind Loading factor; q2 = √ P2 + w2 = 1 (for no wind; P = 0) Difference of temperature; t = 75 – 32.2 = 42.8 °C The working stress is determined by the following formula: 2
f2 [f2 – (k – α t Ef) =
ℓ2 δ2 q2 Ef 24
f22 [f2 – (-147.701 – (19.3x10-6 ) x 42.8 x (0.686x106))) =
2
f22 [f2 +714.36542 ) = 6E+18 24 2
f2 [f2 +714.36542 ) = 3E+17 Work Tension (T2)= f2xa = 555.553321x4.845 = 2691.7
2 2 2 Maximum Sag ; s= ℓ δ q 8 x f2
CONDITION : III
2
2
(260) x (0.373180077) x(1) x( 24
Loading factor; q2 = √ P2 + w2 = 1 (for no wind; P = 0) Temperature = (-) 250c Wind = NIL Difference of temperature; t = 75 – 32.2 = 42.8 °C
2
f2 [f2 – (k – α t Ef) =
ℓ2 δ2 q2 Ef 24
f32 [f3 – (-147.701 – (19.3x10-6 ) x (-34.7) x (0.686x106))) =
2
2
2
(260) x (0.373180077) x(1) x( 24
8 2 f3 [f3+ 311.719083.919470757x10 )=
=
40
=
NIL
=
2
=
U.T.S = FOS
=
2306 Kg
=
=
=
kg/cm2
-
9225 4
2306.25 2.61
(260)2 X (0.373180077)2 X (1)2 X(0.686X106) (24)2 X (685.75851)2
-
6458143809 270872486.8
-
=
75
=
NIL
he following formula: ℓ2 δ2 q2 Ef 24
2
2
2
6
(260) x (0.373180077) x(1) x(0.686x10 ) 24
Kg / cm2
555.553321x4.845 kg/cm2
ℓ2 δ2 q2 Ef 24
2
2
2
6
(260) x (0.373180077) x(1) x(0.686x10 ) 24
3.919470757x108
CONDITION: I Temperature = 32.2 °C Wind = NIL Factor of Safety = 4 Working tension; T1 F.O.S. Working Stress; f1 Loading factor; q1 = √ P2 + w2 = 1 (for no wind; P = 0) k = f1 – ℓ2 δ2 q12Ef/24f12 CONDITION: II Temperature = 75 °C
Sag
CONDITION: II Temperature = 75 °C Wind = NIL Loading factor; q2 = √ P2 + w2 = 1 (for no wind; P = 0) w Difference of temperature; t = 75 – 32.2 = 42.8 °C The working stress is determined by the following formula: f2 2 [f2 – (k – α t Ef) = ℓ2 δ2 q2 2 Ef 24
75
2306.25 4 #DIV/0! 344.6396307
-251.1513693 268829691.4
7.879625
f2 2 [f2 – {– 147.70198 – (19.3 × 10 – 6) × 42.8 × (0.686 × 106)}] = (350)2 × (0.334571723)2 × (1)2 × (0.686 × 106) 24 f2 2 (f2 + 714.36542) = 3.919470757 × 108 ∴ f2 = 555.553321 Kg / cm2 Working tension; T2 = f2 × A = 555.553321 × 4.845 = 2691.656 Kg / cm2 Maximum Sag; s = ℓ2 δ q2 8 × f2 = (350)2 × (0.334571723) × (1) 8 × 555.553321 = 9.22 metres
Sag Calculations for 33KV OH
Sag calculations for 33 KV OH LINE - SRIRENGARAJ ISPAT PARAMETERS:
Value
Basic Span (ℓ) : Ultimate Tensile Strength of Conductor (U.T.S.) : Overall diameter of the Conductor (d) Weight of the Conductor (w) Wind Pressure (P) : Coefficient of linear Expansion (α) Young’s Modulus of elasticity (Final) (Ef) : Young’s Modulus of elasticity (Initial) (Ei) : Maximum temperature (Ambient) Maximum temperature (Conductor) : Minimum Temperature (Ambient) : Minimum Temperature (Conductor) : Every day Temperature : Area of Cross section of Conductor (A) : Factor of Safety (F.O.S.) Factor of Safety (F.O.S.) (Otherwise) : Weight of Conductor per unit area (δ) :
UOM
260 9225 21 0.974 83.38 19.3 X10-6 0.686 × 10 6 0.4675 × 10 6 50 75 -2.5 -2.5 40 2.61 4 2 0.373180077
Minimum Ground Clearance : 7.01 metres
mtrs kg mm kg/m kg/m2 per Deg cel Kg / cm2 Kg / cm2
6
CONDITION :1 Temperature = 32.2 °C Wind = NIL Factor of Saftey = 4 Working tension ; T1 =
U.T.S FOS
=
9225 4
T1=
Working Stress ; f1 =
2306.25
Kg
T1 A
=
f1=
2306.25 2.61 883.6206897
Loading factor; q2 = √ P2 + w2 = 1 (for no wind; P = 0) The working stress is determined by the following formula:
Kg/cm2
f1
k=
=
=
=
k=
883.6206897
883.6206897
883.6206897 538.9814554
CONDITION :II Temperature = 75 °C Wind = NIL Factor of Saftey = 4 Loading factor; q2 = √ P2 + w2 = 1 (for no wind; P = 0)
Difference of Temperature ;t= 75--40 = 35 The working stress is determined by the following formula:
f22 [f2 – (k – α t Ef)
=
f22 [f2 – (538.9814554 – 19.3 X10-6x35 x0.686 × 10 6)
=
f22 [f2+
525.741655 )
=
f22 [f2+
525.7416554 )
=
f2
=
Working tension ; T1 =
U.T.S
x
= =
Maximum Sag ; s=
ℓ2 δ2 q2 8 x f2
=
(260)2X (0.373180077)2 X (1) 8X(f2)
=
#DIV/0!
CONDITION :II Temperature = -2.5 °C Wind = NIL Factor of Saftey = 4 Loading factor; q2 = √ P2 + w2 = 1 (for no wind; P = 0)
Difference of Temperature ;t= 75--40 = 883.6206897 The working stress is determined by the following formula:
f22 [f2 – (k – α t Ef)
=
f22 [f2 – (538.9814554 – 19.3 X10-6x35 x0.686 × 10 6)
=
f22 [f2+
#REF!
)
=
f22 [f2+
#REF!
)
=
Working tension ; T1 =
f2
=
U.T.S
x
= =
Maximum Sag ; s=
ℓ2 δ2 q2 8 x f2
=
(260)2X (0.373180077)2 X (1) 8X(f2)
=
#VALUE!
Sag Calculations for 33KV OH LINE -SRIRENGARAJ ISPAT
133 50 20 70 273
ℓ2 δ2 q12Ef 24f12 (260)2 x (0.373180077)2x(1)2 x (0.686x106) 2
(24) x (883.6206)
6458143796 18738852.56
344.6392343
ℓ2 δ2 q22Ef 24 (260)2 x (0.373180077)2x(1)2 x (0.686x106) 24
6458143796 24
269089324.8
kg/cm2
A
(260)2X (0.373180077)2 X (1) 8X(f2)
#DIV/0!
metres
ℓ2 δ2 q22Ef 24 (260)2 x (0.373180077)2x(1)2 x (0.686x106) 24
#VALUE! 24
#VALUE!
2
kg/cm
A
(260)2X (0.373180077)2 X (1) 8X(f2)
#VALUE!
metres