Padeye Calculation [PDF]

Zitiervorschau

DESIGN OF PADEYE AS PER AISC 360-2005 Section Properties

Py

P 20 THK

a

Px

b

w

Y X

Height of the padeye Height of the eye from top of the beam,h Width of the padeye, w Thickness of the padeye Radius of the padeye Hole diameter Shackle diameter Cross-sectional area Padeye Cross-sectional area Ag Material Properties Yield Strength Ultimate tensile strength

Fy Fu

STAAD input Maximum sling force Sling angle X component of P Px Y component of P Py Code checks Check for Dimensions a b beff w

= = = = = = =

= Selected grade of padeye = =

P

= = = =

= = =

122.5 mm 122.5 mm 2t+16

=

56 mm

=

280 120 320 20 160 75 50

320

mm mm mm mm mm mm mm

6400 mm2 S 275 275 MPa 400 MPa

244.84 66.38 98.099768 224.32802

kN degrees kN kN

Condition a>1.33beff

Fig. C-D5.1 O.K

beff2beff+d

O.K

a) Tensile rupture on the net effective area

Clause

Pn=2×t×beff ×Fu Фt Design strength

=

896 kN

=

0.75 [LRFD] Фt*Pn

=

= 672 kN Pass ratio = 0.36 SELECTED SECTION IS SAFE IN TENSILE RUPTURE

b) For shear rupture on the effective area

Clause Asf

Pn=0 . 6× Fu × Asf = Design strength

1416 kN Фt*Pn

= = =

Pass ratio

= =

1062 kN 0.23

SELECTED SECTION IS SAFE IN SHEAR

c) For bearing on the projected area of the pin Apb

Rn=1 . 8×Fy× Apb = Design strength

495 kN Фt*Pn

=

= = Apb - Projected bearing area

= 371.25 kN Pass ratio = 0.66 SELECTED SECTION IS SAFE IN BEARING

d) For tensile yielding in the gross section

Clause

Pn= Fy × Ag =

Фt

1435.6993350048 kN

=

0.9 [LRFD]

Фt*Pn = 1292.1294015043 kN Pass ratio = 0.19 SELECTED SECTION IS SAFE IN YIELDING

Design strength

=

e)Check for Bending stress Moment developed ,M =Px*h

=

11771972 Nmm

Moment of Inertia,Ixx y Section Modulus,Z = Ixx/y Bending Stress

= = =

fb = M ÷ Z =

Allowable Bending Stress Fb fb

= = < Fb

86603300 mm4 160 mm 541270.63 mm3

21.748773 N/mm2 0.66 * Fy 181.5 N/mm2

SELECTED SECTION IS SAFE IN BENDING Check for Weld size Thickness of weld Moment of Inertia,Ixx y Section Modulus, Z =Ixx/y Moment , M M/Z Area,A P/A P/A + M/Z

= = = = = = = = =

1 11855000 160 74093.75 11771972 158.87942 1340 167.40897 326.28839

mm mm4 mm3 Nmm mm2 N/mm X

Let required size of weld be S Allowable stress in weld

=

100 N/mm2

S×0. 707×100=( P÷ A )+( M ÷Z ) Reqd.Size S = Selected Size =

4.62 mm 6 mm

>S

HENCE O.K

Fig. C-D5.1

D5-1

D5-2 2t(a+d/2) 5900

Section J7

dpin x t 1000 ected bearing area

D2-1

Weld 20

Stiffener plates 10 85

60 X 320

10

Padeye