Probleme Rezolvate in C [PDF]

Zitiervorschau

Rezolvarea ecuatiilor de gradul I (ax+b=0)

#include int main() { int a,b; float x; printf("a="); scanf("%d",&a); printf("b="); scanf("%d", &b); x=-(float)b/a; printf("\nX=%f", x); return 0; }

Rezolvarea ecuatiilor de gradul II (ax^2+bx+c=0)

#include float a,b,c,x1,x2,d; int main() { printf("a="); scanf("%f", &a); printf("b="); scanf("%f", &b); printf("c="); scanf("%f", &c); d=b*b-4*a*c; x1=(-b+sqrt(d))/2*a; x2=(-b-sqrt(d))/2*a; printf("\nx1=%f", x1); printf("\nx2=%f", x2); }

Determinarea minimului a 3 numere folosind operatorul conditional / instructiunea if

#include int main() { int a,b,c; printf("a="); scanf("%d", &a); printf("b="); scanf("%d", &b); printf("c="); scanf("%d", &c); if( aalgoritmica+p->bazeleinformaticii+p->programare1; p->medie=p->medie+p->programare2+p->arhitectura+p->geometrie+p->limbaje+p->structuri; m=p->medie=p->medie/10; printf("Media generala:%.1f\n",m); } } break; case 2:for(i=1;i